Problem 48 : Self powers

Problem Statement

The series, 1¹ + 2² + 3³ + … + 10¹⁰ = 10405071317.

Find the last ten digits of the series, 1¹ + 2² + 3³ + … + 1000¹⁰⁰⁰.

Solution

sum1=0

for i in range(1,1000+1):
    sum1=sum1+(i**i)

val=str(sum1)
val=val[::-1]

print(int(val[0:10][::-1]))

Output

9110846700